MJ10023D View Datasheet(PDF) - ON Semiconductor
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MJ10023
SWITCHING TIMES NOTE
In resistive switching circuits, rise, fall, and storage times
have been defined and apply to both current and voltage
waveforms since they are in phase. However, for inductive
loads which are common to SWITCHMODE power
supplies and hammer drivers, current and voltage
waveforms are not in phase. Therefore, separate
measurements must be made on each waveform to
determine the total switching time. For this reason, the
following new terms have been defined.
tsv = Voltage Storage Time, 90% IB1 to 10% VCEM
trv = Voltage Rise Time, 10–90% VCEM
tfi = Current Fall Time, 90–10% ICM
tti = Current Tail, 10–2% ICM
tc = Crossover Time, 10% VCEM to 10% ICM
An enlarged portion of the inductive switching waveform
is shown in Figure 7 to aid on the visual identity of these
terms.
For the designer, there is minimal switching loss during
storage time and the predominant switching power losses
occur during the crossover interval and can be obtained
using the standard equation from AN–222A:
PSWT = 1/2 VCCIC(tc)f
In general, trv + tfi ` tc. However, at lower test currents
this relationship may not be valid.
As is common with most switching transistors, resistive
switching is specified at 25_C and has become a benchmark
for designers. However, for designers of high frequency
converter circuits, the user orientated specifications which
make this a “SWITCHMODE” transistor are the inductive
switching speeds (tc and tsv) which are guaranteed at 100_C.
RESISTIVE SWITCHING
2.0
VCC = 250 V
1.0
IC/IB1 = 20
TJ = 25°C
0.5
0.2
tr
0.1
0.05
td
0.02
0.4
1.0
2.0
5.0
10
20
40
IC, COLLECTOR CURRENT (AMPS)
Figure 10. Typical Turn–On Switching Times
2.0
VCC = 250 V
1.0
IC/IB1 = 20
VBE(off) = 5 V
0.5
0.2
0.1
0.05
0.02
ts
tf
0.4
1.0
2.0
5.0
10
20
40
IC, COLLECTOR CURRENT (AMPS)
Figure 11. Typical Turn–Off Switching Times
1.0
D = 0.5
0.5
0.2
0.2
0.1
0.1
0.05
SINGLE PULSE
0.01
0.1
1.0
RθJC(t) = r(t) RθJC
RθJC = 0.7°C/W MAX
D CURVES APPLY FOR POWER
PULSE TRAIN SHOWN
READ TIME AT t1
TJ(pk) - TC = P(pk) RθJC(t)
10
100
t, TIME (ms)
Figure 12. Thermal Response
P(pk)
t1
t2
DUTY CYCLE, D = t1/t2
1000
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6
10000
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