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BAT54WS View Datasheet(PDF) - Intersil

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Application Note 1612
ISL6844 Reference Design: ISL6844EVAL3Z
Introduction
This document focuses on Intersil’s solution for the flyback
converter. An inexpensive approach with discrete circuitry has
been adopted instead of an integrated solution. Low cost and
optimal performance are the prime objectives.
Intersil’s superior industry-standard ISL684x family of PWM
controllers would best serve the needs of this design. Some
key features of this family of parts include:
• 40ns peak current sensing
• 1A MOSFET driver
ISL6844 was selected for its large UVLO hysteresis, UVLO start
threshold, and the fact that the converter has been designed
for a maximum operational duty cycle of 50%, thus protecting
the IC by limiting the duty cycle in case of extreme fault
conditions.
Specifications
• Operating Input Voltage: 24V DC ±10%
• Output Voltage: ±15V
• Output Current: 100mA
• Ripple: 50mVP-P
• Switching Frequency: 300kHz
• Topology: DCM Flyback
Design Procedure
Figure 1 shows a simplified circuit of the solution. It is
assumed that loads are balanced for both positive and
negative outputs. The turn ratio of the auxiliary winding is
chosen to be the same as the secondary winding. Figure 2
shows typical operational waveforms of a flyback converter in
discontinuous conduction mode.
Determine the Maximum Duty Cycle and
Transformer Turn Ratio
ISL6844 clamps the duty cycle to 50%. However, in this
converter design, it is assumed that the operating maximum
duty cycle, dmax, will be 35% at the minimum input voltage of
21.6V.
Given the power level, the flyblack converter is designed to
operate in discontinuous conduction mode. The magnitizing
inductance can be calculated using Equation 1:
LM = η ⋅ V----2-I2--N---,--P-M---o--I-u-N--t---⋅⋅---dF----m2s---w-a----x-
(EQ. 1)
=
0.75
---2---1---.--6----2-------0---.--3---5----2---
2 3 300×103
=
23.8 μ H
Where:
η = Converter’s efficiency, assuming 75%
POUT = Total output power
Fsw = Switching frequency
As a result, the peak magnitizing current = 1.06A
The transformer’s turn ratio can be determined from:
n
=
(---V----o---u----t---+-----V----F----)------(--1-----–-----d---2----)
VIN, MIN dMAX
(EQ. 2)
dMAX + d2 < 1
Where:
n = Turns ratio between the primary and the secondary
windings
VF = Forward drop across the diode, assuming 0.6V
d2 = Duty cycle of diode conduction time
d2Tsw is the magnitizing current reset time. Setting d2 to 0.5,
Equation 2 yields the transformer’s turn ratio of 1.
VIN
CIN
CS
RS
DS
1
n
n
OUT
CS
ISL6844
VDD
VIN
VREG
RSENSE
n
D1
COUT1
COUT2
D2
+15V
-15V
FB
CAUX
GND
FIGURE 1. SIMPLIFIED CIRCUIT
November 28, 2011
1
AN1612.1
CAUTION: These devices are sensitive to electrostatic discharge; follow proper IC Handling Procedures.
1-888-INTERSIL or 1-888-468-3774 | Intersil (and design) is a registered trademark of Intersil Americas Inc.
Copyright Intersil Americas Inc. 2010, 2011. All Rights Reserved
All other trademarks mentioned are the property of their respective owners.
 

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