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CXA2513M View Datasheet(PDF) - Sony Semiconductor

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CXA2513M Datasheet PDF : 20 Pages
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CXA2513M
Description of Operation
1. Graphic Equalizer
• Conventional system
VI
R1
Operational amplifier
Vo
RV
R2
CUT-OFF
Z (s)
BOOST
L
C
RO = R1 = R2
R
Fig. 1
Fig. 1 indicates the conventional graphic equalizer system. This circuit performs boost and cut-off near "fO"
controlled by the potentiometer Rv. ("fO" is resonance frequency determined by Z (s) (formed LCR).) The
operation can be seen as follows: When the LCR circuit goes to the far left of Rv, a state of graphic equalizer
becomes maximum cut-off. At that time, assuming transmittance as T (s), the following expression can be
obtained.
Z (s)
T (s) =
Z (s) + Ro
Here as
Z (s) = sL + R + 1
sC
LCS2 + RCS + 1
Then T (s) =
LCS2 + (R + RO) CS + 1
Defining fO as fO =
ωo
2π
, ωo as ωo =
1
LC
, and Q as Q = ωoL
R
, the frequency response can be obtained
at cut-off
Also, when LCR circuit goes to the far right of Rv, a state of graphic equalizer becomes maximum boost. At
that time transmittance is:
Z (s) + RO
LCS2 + (R + RO) Cs + 1
T (s) =
=
Z (s)
LCS2 + RCS + 1
Defining fO, ωo and Q as for cut-off the frequency response can be obtained at boost.
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